Hi sir,

I actived scStr.topology.geometricLayout =true

and use pathloss model type =urban

what effect does these prameters when choose urban scStr.simulation.pathLossModel.alpha = 1;

scStr.simulation.pathLossModel.alpha2 = 3.9;

scStr.simulation.pathLossModel.breakDistance = 50;

scStr.simulation.pathLossModel.averageBuildingHeight = 1

when i choose position for RIS [x,y,z] ex: [200,100,20]

does z=20 for BuildingHeight because ris on height 20m

best regards

Roaa

Dear Roaa,

It means that the buildingâ€™s height is 1 meter, and the RIS is at 20 meters, and therefore the RIS is 19 meters above the rooftop.

To see how this is calulcated, open the file `+Parameters/SimulationParameters.m`

and scroll down to line `2457`

. There you find how these values are used, and what 3GPP document / section the calculation follows.

Best regards,

Bashar

Thanks for response, i want to question about alpha when chose pathloss exponent for urban from 2.7 to 3.5 ,the throughput becomes =zero why ??

With the higher exponent the path loss becomes higher, and therefore the recevied signal becomes too weak to be detected. In this case, higher transmit powers should be used, or you should lower the modulation order and code rate used.